I know the coat is unfashionable but I’m not going to throw it away. I’ll keep it () that style. comes into fashion again.A、whenB、untilC、sinceD、as

题目
I know the coat is unfashionable but I’m not going to throw it away. I’ll keep it () that style. comes into fashion again.

A、when

B、until

C、since

D、as

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更多“I know the coat is unfashionable but I’m not going to throw it away. I’ll keep it () that style. comes into fashion again. ”相关问题

  • 第1题：

    -- Ann is in hospital.

    -- Oh, really? I __ know. I __ go and visit her.

    A. didn’t; am going to B. don’t; would

    C. don’t; will D. didn't; will


    正确答案：D

  • 第2题：

    I′m sorry I can′t see you immediately;but if you′d like to take a seat,I′ll?be with?you__________.

    A.for a moment
    B.in a moment
    C.for the moment
    D.at the moment

    答案：B
    解析：
    【考情点拨】考查词组词义辨析。【应试指导】句意：对不起，我不能马上见你；但是如果你坐下来等我的话，我过一会儿就可以。for a moment一会儿（表示时间段）；in a moment过一会儿：for the moment暂时；at the moment此时，此刻。

  • 第3题：

    下面（）仅输出m的大于1的最小因子。

    A．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); break; }

    B．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); continue; }

    C．for (i =2; i＜=m-1; i++) if (m % i == 0) { printf("%d is 最小因子n", i); }

    D．i=2; while (m % i != 0) i++; printf("%d is 最小因子n", i);


    A

  • 第4题：

    I'm sure I'll be able to amuse myself for a few hours.

    A:treat
    B:hold
    C:entertain
    D:keep

    答案：C
    解析：
    本句意思：我相信我能够自娱自乐几个小时。amuse意思是“娱乐，使消遣”，与entertain（娱乐）意思相同。treat对待；hold拿住，握住；keep保持。

  • 第5题：

    I'm sure I'll be able to amuse myself for a few hours.

    A:entertain
    B:treat
    C:hold
    D:keep

    答案：A
    解析：
    本句意思：我相信我将能自娱自乐数小时。amuse逗笑，逗乐，娱乐。entertain使有兴趣，使快乐，娱乐；treat对待，款待；hold拿着，抱住，托住，抓住；keep（使）保持，处于。

  • 第6题：

    下面（）是正确的判断素数程序（m＞1)。

    A．j=0; for (i =2; i＜=m-1; i++) if (m % i != 0) j++; if(j==m-2) printf(“%d是素数n", m);

    B．j=0; for (i =2; i＜=m-1; i++) if (m % i == 0) j++; if(j==0) printf(“%d是素数n", m);

    C．flag=0; for (i =2; i＜=m-1; i++) if (m % i == 0) flag=1; if(flag==0) printf(“%d是素数n", m);

    D．for (i =2; i＜=m-1; i++) if (m % i == 0) i=m+2; if(i==m+3) printf(“%d是素数n", m);


    D

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